4[2x+1]-3[x-2]=10+5x

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Solution for 4[2x+1]-3[x-2]=10+5x equation: 


Simplifying
4[2x + 1] + -3[x + -2] = 10 + 5x

Reorder the terms:
4[1 + 2x] + -3[x + -2] = 10 + 5x
[1 * 4 + 2x * 4] + -3[x + -2] = 10 + 5x
[4 + 8x] + -3[x + -2] = 10 + 5x

Reorder the terms:
4 + 8x + -3[-2 + x] = 10 + 5x
4 + 8x + [-2 * -3 + x * -3] = 10 + 5x
4 + 8x + [6 + -3x] = 10 + 5x

Reorder the terms:
4 + 6 + 8x + -3x = 10 + 5x

Combine like terms: 4 + 6 = 10
10 + 8x + -3x = 10 + 5x

Combine like terms: 8x + -3x = 5x
10 + 5x = 10 + 5x

Add '-10' to each side of the equation.
10 + -10 + 5x = 10 + -10 + 5x

Combine like terms: 10 + -10 = 0
0 + 5x = 10 + -10 + 5x
5x = 10 + -10 + 5x

Combine like terms: 10 + -10 = 0
5x = 0 + 5x
5x = 5x

Add '-5x' to each side of the equation.
5x + -5x = 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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